Question

An elevator descends into a mine shaft at the rate of 5 m per minute. What will be its position after 2 hours?​

Answer 1

Answer:

position will be=15-300=-285=285m below the ground.

Answer 2

★ Answer ★

Since the elevator is going down, so the distance covered by it will be represented by a negative integer.

Change in position of the elevator in one minute = – 5 m

Position of the elevator after 120 minutes = (–5) × 120 = – 1000 m, i.e., 1000 m below down from the starting position of elevator.

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CreativeAB

• The Genius •