An elevator descends into a mine shaft at the rate of 5 m/min. What will be its position after one hour? If it begins to descend from 35 m above the ground, what will be its position after 30 minutes?
Answers
Answered by
0
Answer:
Since, the elevator going down, so the distance covered by it will be represented by a negative integer.
Change in position of elevator in one minute = −5 m.
Position of the elevator after 60 minutes = (−5)×60=−300 m
That means the position of the elevator will be 300 m below ground level.
Step-by-step explanation:
Similar questions