Math, asked by firaashassan9, 18 days ago

An elevator descends into a mine shaft at the rate of 5 m/min. What will be its position after one hour? If it begins to descend from 35 m above the ground, what will be its position after 30 minutes?​

Answers

Answered by azamzaid2007
0

Answer:

Since, the elevator going down, so the distance covered by it will be represented by a negative integer.

Change in position of elevator in one minute = −5 m.

Position of the elevator after 60 minutes = (−5)×60=−300  m  

That means the position of the elevator will be 300 m below ground level.

Step-by-step explanation:

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