Question

an elevator descends into a mine shaft at the rate of
5m/min. if it descends starts from 50m above ground level, how long it take to reach - 150m.
​

Answer 1

Answer:

We know that the mine shaft descends at a rate pf 5 m/min, and it has to go down 150 m but is already at a 50 m height hence it needs to go down 200 m

Step-by-step explanation:

total descending dist.=200 m

speed of the shaft = 5 m/min

we know that time=dist/speed hence

200 m/5 m/min = 40 min/ 0.666...hrs