An elevator descends into a mine shaft at the rate of 5m/min. If the descent starts from 20m above the ground level. How long will it take to reach -370m?
Answers
Answered by
5
Answer:
total distance it needs to cover = -370-20 = -390m
as it is 20 m above plus it also needs to go 370 metre down. so = 390m
Now,
speed = 5m/min
speed = distance /time taken
time taken = 390/5 = 78min = 1hour 18mins
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Answered by
4
Answer:
1hr 10 mins
Step-by-step explanation:
total distance = -370+20 = -350 m
time taken = -350 ÷5
= 70 mins
=1hr 10 mins
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