Question

An elevator descends into a mine shaft at the rate of 5m / min . If the descent  starts from 50m above the ground level, how long will it take to reach -250 m

Answer 1

Answer:

15m

Step-by-step explanation:

(i) Displacement = Velocity x Time = -5 m/min x 60 min = -300 m.

(ii) Displacement from initial position = Velocity x Time = -5 m/min x 45 min = -225 m.

However, since we started 15 m above ground, displacement from the ground level = -225 + 15 m = -210 m.