Math, asked by meghrajy3, 21 hours ago

An elevator descends into a mine shaft at the rate of 5m/min, If the descent
starts from 10m above the ground level, how long will it take to reach -350m.​

Answers

Answered by pritishpr7swain
0

Answer:

72 Min which is 1hr 12min

Step-by-step explanation:

The lift starts from 10m above the ground and goes to -350m. So the total distance covered is 360m. So by dividing with the speed

360/5m/min = 72 min

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