An elevator descends into a mine shaft at the rate of 5m/min, If the descent
starts from 10m above the ground level, how long will it take to reach -350m.
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Answer:
72 Min which is 1hr 12min
Step-by-step explanation:
The lift starts from 10m above the ground and goes to -350m. So the total distance covered is 360m. So by dividing with the speed
360/5m/min = 72 min
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