An elevator descends into a mine shaft at the rate of 5m/min. If the decend starts from 15 m above the ground, how long will it take to reach 350 m deep from the ground?
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total distance to cover 350+15=365
v=5m /min
using d=u×t
365=5×t
t=365/5=73 seconds
v=5m /min
using d=u×t
365=5×t
t=365/5=73 seconds
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