Question

- An elevator descends into a mine shaft at the rate of 5m per minute. If the descent starts from 8m above the ground level , how long will it take to reach 42m [means - 42m] below the ground level ?​

Answer 1

Answer:

The time taken is 9.9 minutes

Step-by-step explanation:

D1= 5m

T1= 1 minute

=60s

So the speed is

S=D1/T1

=5/60

=0.084m/s

So, the lift has to descend from 8m above ground to 42m under ground

So, D2=(8+42)m

=50m

Speed=0.084m/s

So, T2=D2/S

=50/0.084

=595s

=9.9 minutes

So, the lift takes 9.9 minutes to travel from 8m above the ground to 42m into the mine.