Question

An elevator descends into a mine shaft at the rate of 5mts per minute. What will be its position after one hour?

Answer 1

Answer:

Since, the elevator going down, so the distance covered by it will be represented by a negative integer.

Change in position of elevator in one minute = −5m.

Position of the elevator after 60 minutes = (−5)×60=−300 m

i.e. 300 m below ground level.