An elevator descends into a mine shaft at the rate of 6 meters per minute. If the
starts from 10 m above the ground level, how long will it take to reach - 350 m.
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Answer:
Step-by-step explanation:
Displacement=360m
u=6
g=+10
360= 6/60t+5t^2
Solve the equation using quadratic formula, then take the +ve value!
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