Question

An elevator descends into a mine shaft at the rate of 6 meters per minute. If the descent
starts from 10 m above the ground level, how long will it take to reach - 350 m​

Answer 1

Answer:

Distance descended is denoted by a negative integer,

Initial height

=

+10 m

Final Depth

=

−350 m

Total distance to be descended by the elevator

=

(−350)−

(+10)=

−360 m

Given, the time is taken by the elevator to descend

−6 m=

1 minute

Thus, time taken by the elevator to descend

−360 m=

(−6)

(−360)

------- [from the formula :

speed=

time

distance

]

= 60 minutes

Answer 2

Answer:

Distance descended is denoted by a negative integer.

Initial height = + 10 m

Final depth = -350 m

Total distance to be descended by the elevator = (-350) - (+ 10) = -360 m

Time taken by the elevator to descended - 6 m = 1 min

Thus, time taken by the elevator to descend - 360 m = (-360) ÷ (- 6)

= 60 minutes

= 1 hour