Question

an elevator descends into a mine shaft at the rate of 6 metre per minute if the decent is start from 10 metre above the ground level how long will it take to reach 350 deep from the ground

Anyone plz solve my problem​

Answer 1

Answer:

1 hour

Step-by-step explanation:

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,

The elevator has to travel 10m till the ground, then 350 m more.

So, the total distance to travel is 360 m

If the elevator's speed is 6 metres/minute,

Then

Time= Distance/Speed

= 360/6

=60 minutes

=1 hour

Thus the elevator would take 1 hour to reach its destination.

Hope it will help you !

Answer 2

Answer:

Time taken is 1 hour or 60 minutes or 3600 seconds

Step-by-step explanation:

Speed = 6 m/min = 0.1 m/s

Distance = 10 metres above ground + 350 metres below ground = 360 m

Time = ?

$Speed = \frac{Distance}{Time}$

⇒ $Time = \frac{Distance}{Speed}$

             $= \frac{360 m}{0.1 m/s} \\= 3600 s = 60 min = 1 h$

Please mark it as the brainliest answer :)

Hope it helps you :))