Question

An elevator descends into a mine shaft at the rate of 6 meters per minute. If the descent
starts from 10 m above the ground level, how long will it take to reach – 350 m.

Answer 1

Answer: The elevator has to travel 10m till the ground, then 350 m more. Thus the elevator would take 1 hour to reach its destination.

Step-by-step explanation:

Answer 2

Answer:

Distance descended is denoted by a negative integer.Initial height = + 10 mFinal depth = -350 mTotal distance to be descended by the elevator = (-350) - (+ 10) = -360 mTime taken by the elevator to descended - 6 m = 1 minThus, time taken by the elevator to descend - 360 m = (-360) ÷ (- 6)= 60 minutes

Step-by-step explanation:

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