Question

an elevator descends into a mine shaft at the rate of 6 metre per minute. if it descends start from 10 metre above the ground level how long will it take to reach the shaft 350 below the ground level?​

Answer 1

Answer:

Step-by-step explanation:

Starting position of mine shaft is = 10m above ground

but,

it moves in opposite direction so it travels the distance (-350 m ) below the ground.

Total distance covered by mine shaft = 10m - (-350m)

= 10 + 350

= 360m

Now, taken to cover a distance of 6m by it = 1 minute

Time taken to cover a distance of 1m by it = \frac{1}{6\ }\min  

6  

1

​

min

Therefore, tie taken to a cover a distance of 360m = \frac{1}{6}\times\ 360\ =\ 60\ \min\ \  

6

1

​

× 360 = 60 min  

60 minutes = 1 hour

thus, in one hour the mine shaft reaches = 350 below the ground.

Answer 2

Answer:

this would help for sure