an elevator descends into a mine shaft at the rate of 6 meters per minutes. If the decent starts from 20 m above the ground level, how long will it take to reach -340m?
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Since it starts from 20 m total distance will be 20 + 340 = 360m
rate is 6m/min
so time taken = 360 / 6 = 60 min
or 1 hour
sharmaatul9929:
thanks.. my dear
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