Question

An elevator descends into a mine shaft at the rate of 6 mitres per minute. If the descent starts from 20 m above the ground level, how long will it take to reach-340

Answer 1

$\mathfrak{hey \: bro}$

Time = 6metres/minute.

$\pink{according \: to \: question}$

It starts from 20 m above the groun level.

$\red{total \: distance = 340 + 20 = 60}$

=360.

Time =6

Distance =360÷6=60 minute

=1hour ans.

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