Question

an elevator descends into a mine shaft at the rate of 6 cm/sec.if its start from 100 cm below ground level , how long will it take to reach 216 cm below ground level​

Answer 1

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,

The elevator has to travel 10m till the ground, then 350 m more.

So, the total distance to travel is 360 m

If the elevator's speed is 6 metres/minute,

Then

Time= Distance/Speed

        = 360/6

        =60 minutes

        =1 hour

Thus the elevator would take 1 hour to reach its destination.

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