Math, asked by gg20012007, 1 year ago

An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts
from 10 m above the ground level, how long will it take to reach (- 350 )m.​

Answers

Answered by sameer2328
7

Answer:

60 minutes,because the total time taken=(350+10)÷6

Answered by nationalenvirocleand
10

Answer:

1 hour

Step-by-step explanation:

Bro this is in 7th class NCERT Book

Speed of elevator = 6metre/minute

It is 10metre above ground and want to go 350metre below ground

So it will add means 10+350=360

Now devide 360/6 = 60 minutes (1hour)

As simple is that

Hope it helps bro

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