An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts
from 10 m above the ground level, how long will it take to reach (- 350 )m.
Answers
Answered by
7
Answer:
60 minutes,because the total time taken=(350+10)÷6
Answered by
10
Answer:
1 hour
Step-by-step explanation:
Bro this is in 7th class NCERT Book
Speed of elevator = 6metre/minute
It is 10metre above ground and want to go 350metre below ground
So it will add means 10+350=360
Now devide 360/6 = 60 minutes (1hour)
As simple is that
Hope it helps bro
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