An elevator descends into a mine shaft at the rate of 6 m/min.If the descentstarts from 10m abovethe ground level,how long will it take to reach -350m
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the distance between 10m and -350m is 360m and if the rate is 6m/min so
The time taken is 360m÷6m/min=60mins
The time taken is 360m÷6m/min=60mins
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