Math, asked by bonitatheres200, 1 year ago

An elevator descends into a mine shaft at the rate of 6 m/min. If the descend
starts from 20 meter above the ground level, how long will it take to reach - 340m?

Answers

Answered by niku19
1
-340m represent that is below the ground level.
total distance covered by elevator.
=20m+340m
=360m
speed of elevator =6m/mm
time taken to reach at bottom
t =d *s
=360 *6
=60minutes
=1hour
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