Math, asked by ambikaupdhaya2020, 11 months ago

An elevator descends into a mine shaft
at the rate of 6 m/min. If the descent
starts from 10 m above the ground level,
how long will it take to reach - 350m

Answers

Answered by chandradeep1612005

17

Answer:

Total d=350+10=360m

speed or rate of elevator is 6m/60s=0.1m/s

total t = d/speed=360/0.1=3600 sec =60 min

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