Question

An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach – 350 m? (descends = goes down) *

1 point

56.66 min

58.33 min

55 min

60 min

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Answer 1

The answer is 60 min.

The calculations is as follows:

The total distance the elevator has to travel is (350 +10) m = 360m

The speed given is 6m/min.

Let time taken be = x

$speed = \frac{ distance}{time}$

Now, putting these values in the formula, we get

$6 = \frac{360}{x}$

$x = \frac{360}{6}$

$x = 60$

Hence, the answer is 60 minutes.

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