An elevator descends into a mine shaft at the rate of 6 m /min .If the descent starts from 10m above ground level, how long will it take to reach -350 m?
Answers
Answered by
5
Answer:
350+10=360.
speed =6m/min. speed
=distance by time
=360 by 6 min =60 min=1hr.
It takes 1 Hr
MARK ME AS BRAINLIEST !!
Answered by
4
Answer:
Since the speed is 6m/min , time taken to reach -340 m = 360/6 = 60 min or 1 hr .
Step-by-step explanation:
hope it helps you
Similar questions