An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach – 350 m.
NCERT Class 7th Mathematics Chapter 1 Integers
Answers
Answered by
41
speed of the elevator=6 m/min
total distance =350 + 10 =360m(as it starts from 10m above the ground level)
time taken=(360÷6)=60min
or 1hour ans.
total distance =350 + 10 =360m(as it starts from 10m above the ground level)
time taken=(360÷6)=60min
or 1hour ans.
Answered by
18
The rate of 6m/min means that, in every minute, it goes down by 6m
We have 10 above the ground and 350 m below the ground
Note:
-350 m, means it is 350 m below the ground
Total distance = 10 + 350
= 360 m
Time taken = 360/6
= 60 minutes
OR
1 hour
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