An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from
10 m above the ground level, how long will it take to reach -350 m.
Answers
Answered by
1
Answer:
1 hr, 60 mins I calculated the steps in my mind
Answered by
7
Answer:
The time taken is 1 hour.
Step-by-step explanation:
Given :
An elevator descends into a mine shaft at the rate of 6 m/min.
To find :
the time taken to reach -350 m if the descent starts from 10 m above the ground level.
Solution :
Speed of the elevator = 6 m/min
Initially, the elevator is at 10 m above the ground level.
It should reach -350 m.
Distance travelled = 10 - (-350)
= 10 + 350
= 360 m
We know that,
Speed = Distance covered/time taken
6 m/min = 360/t
t = 360/6
t = 60 min (1 hour)
The required time taken is 1 hour
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