Question

An elevator descends into a mine shaft at the rate of 6 m/min if the descent start from 10m above the ground level , how long will it take to reach -350m?​

Answer 1

Step-by-step explanation:

the answer is 60 min or 1 hr

Answer 2

Answer:

Starting position of mine shaft is 10 m above the ground but it moves in opposite direction so it travels the distance (–350) m below the ground.

So total distance covered by mine shaft = 10 m – (–350) m = 10 + 350 = 360 m

Now, time taken to cover a distance of 6 m by it = 1 minute

So, time taken to cover a distance of 1 m by it = 1/6minute

Therefore, time taken to cover a distance of 360 m = 1/6 x  360 = 60 minutes = 1 hour  

(Since 60 minutes = 1 hour)

Thus, in one hour the mine shaft reaches –350 below the ground.