Math, asked by sharan4691, 5 hours ago

An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m

above the ground level, how long will it take to reach – 350 m.​

Answers

Answered by poonamray2004
0

Answer:

people have a very different view than they have a chance

Answered by SaptakGhosh
1

Answer:

As it started 10m above the ground it have to cover = (350+10) = 360m

For 6m the time is 1 second

For 1m the time is 1/6 second

For 360m the time is 360/6 = 60second

HOPE IT WILL HELP YOU

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