An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach -350 m? *
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Answered by
1
Answer:
53 minutes
Step-by-step explanation:
15+250=265
24/8=53 minutes
Answered by
0
Answer:
Answer · Speed of elevator = 6m/min · It starts from = 20m above ground · It Reaches to = 340m below ground · Distance it covers = 340 + 20 = 360m.
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