an elevator descends into a mine shaft at the rate of 6 m/min .if his descents. starts from 10 m above the ground level how long will it take to reach -350 m
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Hi dear,
here is ur solution
speed of elevator =6m/min=0.1m/sec
the distance that elevator has to complete
=10+350=360m
according to formula
Time= Distance/Speed
Time to reach -350m is=360/0.1=3600sec
=3600/60=60min=1hr
so the elevator will take 1hr to reach the -350m to ground
I hope it will help u. -Thanks
here is ur solution
speed of elevator =6m/min=0.1m/sec
the distance that elevator has to complete
=10+350=360m
according to formula
Time= Distance/Speed
Time to reach -350m is=360/0.1=3600sec
=3600/60=60min=1hr
so the elevator will take 1hr to reach the -350m to ground
I hope it will help u. -Thanks
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