Question

An elevator descends into a mine shaft at the rate of 6m /mins if the descent starts from 10m above the ground level how long will take to reach-350m

Answer 1

Step-by-step explanation:

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,

The elevator has to travel 10m till the ground, then 350 m more.

So, the total distance to travel is 360 m

If the elevator's speed is 6 metres/minute,

Then,

Time= Distance/Speed

       = 360/6

       =60 minutes

       =1 hour

∴Thus the elevator would take 1 hour to reach its destination.