an elevator descends into a mine shaft at the rate of 6m/minute. if the descend starts from 10m above the ground level, how long will it take to reach -350m
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Answered by
2
Answer:
Thus, the elevator will reach –350m from 10m in 1 hour.
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Answered by
3
Answer:
60min
Step-by-step explanation:
speed=6m/min
total distance=10m+ 350 (as it start from 10m and goes till 350m)
time=?
t=d/s
=360/6
=60min
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