An elevator descends into a mine shaft at the rate of 6m/min. If the descent starts from 10m above the ground level, how long will it take to reach -370 m.
Answers
Answered by
45
Answer:10+370= 380(whole distance)
380÷6=63.333
answer=63 min(rounded figure)
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Step-by-step explanation:
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6
Given,
Descending rate of the elevator = 6 m/ minute
The descent from 10 m above the ground level
To Find,
Time taken to reach a distance of -370m =?
Solution,
Total distance to descent = 370 + 10
Total distance to descent = 380m
Time taken = Total DIstance / Descending rate
Time taken = 380/ 6
Time taken = 63.3 minutes
Time taken = 63 minutes approx.
Hence, it will take 63 minutes to reach -370 m.
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