An elevator descends into a mine shaft at the rate of 6m/min. If the elevator's descend starts from 10 m above the ground level, how long will it take to reach -380 m?
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Answer:
1 hr 5 min =65 min
Step-by-step explanation:
380+10 =390
390 divided by 6 =65 min =1hr 5 min
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