Math, asked by warrior1719, 9 months ago

an elevator descends into a mine shaft at the rate of 6m/min. if the descent starts from 10m above the ground level, how long will it take to reach -350m?​

Answers

Answered by aquialaska
10

Answer:

Elevator take 1 hour to reach -350 m.

Step-by-step explanation:

Given:

Speed of the elevator = 6 m/min

Elevator starts 10 m above ground level.

Elevator travel to -350 m.

⇒ Elevator travel to 350 m below ground level.

To find: Time taken by elevator to reach 350 m below ground level.

Total distance traveled by elevator = 350 + 10 = 360 m

Time taken to travel 360 m = 360/6 = 60 minutes = 1 hour.

Therefore, Elevator take 1 hour to reach -350 m.

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