Math, asked by KoushikNewar, 10 months ago

An elevator descends into a mine shaft at the rate of 6m/min.What will be its position after one hour?If it begins to descend from 20m above the ground, what will be its position after 45 minutes? please write full statement.

given that,
an elevator descends in 1 min=6meter
so, after 45 min =(6×45)meter=270meter
but elevator began to descend from 20meter above the ground,then it's new position will be,

270metr-20metr=250metr​

Answers

Answered by Abhiram2830r
6

Answer:

5

Step-by-step explanation:

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