Question

An elevator descends into a mine shaft at the rate of 6m/min. if the descend starts from 10m above the ground level how long will it take to reach -,350m
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Answer 1

Answer:

1 hour

Step-by-step explanation:

Answer 2

it twill take  60 min or 1 hour to reach -350 m

Step-by-step explanation:

as the elevator is 10 m above the ground and it has to descend -350 m ,

taking groung level as 0 ,

the total height elevator has to travel is : 360 m  

10 (from above the ground to the ground)+ 350 (from ground level into the mine shaft )  = 360

now ,

speed = $\frac{distance}{time}$

time = $\frac{distance}{speed}$

      =$\frac{360}{6}$

    = 60 min .

or 1 hour .