Question

an elevator descends into a mine shaft at the rate of 6m/min.if the descent starts from 10n above the ground level ,how long will it take to teach -350m​

Answer 1

Step-by-step explanation:

-350-10 METRE (BECAUSE THE DESCENT STARTS FROM 10 METRE ABOVE)

= -360

NOW, DIVIDE -340 BY 6

-360÷6

= 60 MINUTES WHICH IS EQUAL TO ONE HOUR

SO THE ANSWER IS 60 MINUTES, WHICH CAN ALSO BE SAID AS ONE HOUR.

HOPE IT HELPS YOU....!