Question

an elevator descends into a mine shaft at the rate of 6m/min. If the descent starts from 10m above the ground level how long will it take to reach -350m deep under the ground​

Answer 1

Answer:

3600 seconds

Step-by-step explanation:

total distance the elevator has to cover = 360 metre

velocity = 6m/min   =  6/60 m/s   =   0.1 m/s

Use the formula t= S/v  

           t = 360/0.1    

           t = 3600 seconds  = 60 minutes   = 1 hour

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