an elevator descends into a mine shaft at the rate of 6m/min. If the descent starts from 10m above the ground level how long will it take to reach -350m deep under the ground. please help fast Give clear explanation also
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ANSWER ;
3600 seconds
Step-by-step explanation:
total distance the elevator has to cover = 360 metre
velocity = 6m/min = 6/60 m/s = 0.1 m/s
Use the formula t= S/v
t = 360/0.1
t = 3600 seconds = 60 minutes = 1 hour
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