an elevator descends into a mine shaft at the rate of 6m / min . if the descends start from 20m above the ground level,how long will it take to reach 520m below the ground level
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Answer:
The answer is 520+20 by 6 = 90 mins or 1.5 hours
Step-by-step explanation:
Since it started 20 m above the total distance being covered becomes 520+20=540
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