An elevator descends into a mine shaft at the rate of 6m/min. If the descent starts from 20m
above the ground level, how long will it take to reach -370m?
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Answer:
speed of the elevator=6m/min
total distance =350+10 =360m(as it start from 10m above the ground level )
time taken=(360÷6) 60min
or 1hour ans.
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