Question

An elevator descends into a mine shaft at the rate of 6m/min.What will be its position after one hour?If it begins to descend from 20m above the ground, what will be its position after 45 minutes? please write full statement.

Answer 1

An elevator descends into mine shaft at the rate of 6 meter per minute.
So, for 1 min elevator descends 6 meters.
The position of the elevator after one hour =

We know,
 1 hour =60 min
 60 min x 6 meters=360 meters..
But the elevator began to descend from 20 meters above.

So,
360 - 20= " 340 meters."
It's position after 45 mins  = 45 meters x 6 mins
                                          = 270 meters.
The elevator has descended from 15 meters above
So,
270 - 15 meters = 225 meters

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Answer 2

Answer:

The answer is 250m

Because if we will multiply 6 to 20 ans is 270 .

After that we will subtract 270 from 20 we will get the answer - 250m .

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