Question

An elevator descends into a mine shaft at the rate of 6m / min . If the descent starts from 10 m above the ground level, how long will it take to reach - 350 m.​

Answer 1

$\huge\colorbox{pink}{Solution ࿐❤}$

Distance descended is denoted by a negative integer.

Initial height =+10 m

Final depth =-350 m

Total distance to be descended by the elevator=(-350)-(+10)=-360 m

Time taken by the elevator to descend - 6m = 1min

Thus, time taken by the elevator to descend - 360m = (- 360) / (- 6)

= 60 minutes =1 hour

Hope it helps you ❤

Answer 2

Solution :-

Distance descended is denoted by a negative integer.

Initial height = + 10 m

Final depth = -350 m

Total distance to be descended by the elevator=(-350)-(+10)=-360 m

Time taken by the elevator to descend - 6m = 1min

Thus, time taken by the elevator to descend - 360m = (- 360) / (- 6)

= 60 minutes = 1 hour

Hope it helps you ❤