An elevator descends into a mine shaft at the rate of 6m/min. If the descent starts from 10m above the ground level,how long will it take to reach -350m.
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Answer:
110 minutes or 1 hour and 50 minutes
Step-by-step explanation:
Original Distance = 10m
Distance to be reached = -650m
Total distance covered = 650+10 = 660m
Speed = 6m/min
Time = 660/6 = 110 min
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