Question

An elevator descends into a mine shaft at the rate of 6m/min.The descends starts from 10m above sea level.
(1) Where will it reach in 20 minutes?
(2)How long will it take to reach a depth of -350m?​

Answer 1

Answer:

1) Ans=> 70 m

2) Ans=> 60min or 1hour

Step-by-step explanation:

For 1)

Speed of the elevator=6 meter/minute

Starting point=-10m

A)In 10 minutes, the distance covered is= 6m ×10=60 m

As the elevator started from -10m and descended 60m more, it reached -10m-60m

which is -70m

ANS -70 M

For 2)

An elevator descends into a mine shaft at the rate of 6 m/min.

The descent starts from 10 m above the ground level.

Total distance  10 + 350 m

Total distance  360 m

Given that speed of elevator  6 m/min

So,

Time= distance/speed

        = 360/6

        =60min or 1 hr

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