An elevator descends into a mine shaft at the rate of 6m/min.The descends starts from 10m above sea level.
(1) Where will it reach in 20 minutes?
(2)How long will it take to reach a depth of -350m?
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Answer:
1) Ans=> 70 m
2) Ans=> 60min or 1hour
Step-by-step explanation:
For 1)
Speed of the elevator=6 meter/minute
Starting point=-10m
A)In 10 minutes, the distance covered is= 6m ×10=60 m
As the elevator started from -10m and descended 60m more, it reached -10m-60m
which is -70m
ANS -70 M
For 2)
An elevator descends into a mine shaft at the rate of 6 m/min.
The descent starts from 10 m above the ground level.
Total distance 10 + 350 m
Total distance 360 m
Given that speed of elevator 6 m/min
So,
Time= distance/speed
= 360/6
=60min or 1 hr
Pls bro it's took a lot of time pls mark as brainliest
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