Question

An elevator descends into a mine shaft at the rate of 6m/min .The distance starts from 10 m above sea level.

(i) Where will it reach in 20 minutes?

(ii) How long will it take to reach a depth of -350m?​

Answer 1

Answer:

please mark as brilliant

Answer 2

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(i)-110 m

(ii) 60 min

Given

• An elevator descends into a mine shaft at the rate of 6m/min .The distance starts from 10 m above sea level

To find

• (i) Where will it reach in 20 minutes?

• (ii) How long will it take to reach a depth of -350m?

Solution

• Speed of the elevator=6 meter/minute

• Starting point = 10m

★I)

• In 20 minutes, the distance covered is= 6m ×10=120 m

• As the elevator started from -10m and descended 60m more, it reached (10- 120)m

• → -110 m

★II)

• Required depth = -350 m
• Required dist to be covered = -350-10 = -360 m i.e. 360 m
• Therefore Time required to cover it = Dist/ speed
• → 360/ 6
• → 60 min

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