An elevator descends into a mine shaft at the rate of 6m/ min if the descents starts from 10 m above the ground level ,how long will it take to reach -350 m.
Answers
Answered by
1
Answer:
Total distance elevator has to travel = Initial position - final position
= 10-(-350)
= 10 + 350
= 360 m
Now,
Elevator descends at rate 6m/min
Elevator travels 6 m in = 1 minute
1 Elevator travels 1 m in = 1/6minute
Elevator travels 360 m in =1/6 x 360 minutes
= 60 minutes
= 1 hour
Answered by
0
Answer:
60min or 1hr
Step-by-step explanation:
starting distance of elevator from ground level=10m
ending distance of elevator from ground level=350m
total distance to be covered by elevator=350+10=360
speed of elevator = 6m/min
time=distance/Speed
time=360/6
time=60min= 1hr
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