An elevator descends into a mine shaft at the rate of 6m/min . If the descend starts from 10m above the ground level how long will it take to reach the shaft 350m above the ground level
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hi friend,
So , A.T.Q.
the rate of descend of elevator= 6m/min
if , the descend of elevator starts from 10m above the ground level. so , it will take 60min (1 hour) to reach at shaft .
total length from elevator to shaft = 350m + 10m = 360m
total time taken by elevator to reach at shaft = 360 ÷6
= 60 min (1 hour )
I am not sure about answer, but hope it helps.......
So , A.T.Q.
the rate of descend of elevator= 6m/min
if , the descend of elevator starts from 10m above the ground level. so , it will take 60min (1 hour) to reach at shaft .
total length from elevator to shaft = 350m + 10m = 360m
total time taken by elevator to reach at shaft = 360 ÷6
= 60 min (1 hour )
I am not sure about answer, but hope it helps.......
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