Math, asked by juliedepala04, 12 hours ago

an elevator descends into a mine shaft at the rate of 6m/min .if the descent starts from 8m above the ground level, how long will it take to reach ---42m(Means -- 42m) below the ground level​

Answers

Answered by siddiqkazi
3

Answer:

Good Question

Step-by-step explanation:

If mineshaft moves with a speed of 6M/M.

it decents start from 8M above and goes (-42 below)

MINUTES METRE

6 1

? 8+(-42)=-50

=(--50) ×6= 300

ANS--IT WILL TAKES 300M

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Answered by anjumanyasmin
0

From the given question the correct answer is :

300M

300M will it take to reach ---42m(Means -- 42m) below the ground level​

 

If mine shaft moves with a speed of 6M/M.

it decents start from 8M above and goes (-42 below)

MINUTES METRE

6 1

8+(-42)=-50

=(--50) ×6= 300

ANS--IT WILL TAKES 300M

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