Question

An elevator descends into a mine shaft at the rate of 6m/min. If the descent starts from 10m above the
ground level, how long will it take to reach – 350m

Answer 1

speed of the elevator=6 m/min

total distance =350 + 10 =360m(as it starts from 10m above the ground level)

time taken=(360÷6)=60min

or 1hour ans.